Optimal. Leaf size=66 \[ -\frac{5 \tan (c+d x)}{2 a^3 d}+\frac{7 \tanh ^{-1}(\sin (c+d x))}{2 a^3 d}-\frac{\tan (c+d x) (1-\sec (c+d x))}{2 a^3 d}-\frac{x}{a^3} \]
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Rubi [A] time = 0.0908163, antiderivative size = 66, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {3888, 3775, 3914, 3767, 8, 3770} \[ -\frac{5 \tan (c+d x)}{2 a^3 d}+\frac{7 \tanh ^{-1}(\sin (c+d x))}{2 a^3 d}-\frac{\tan (c+d x) (1-\sec (c+d x))}{2 a^3 d}-\frac{x}{a^3} \]
Antiderivative was successfully verified.
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Rule 3888
Rule 3775
Rule 3914
Rule 3767
Rule 8
Rule 3770
Rubi steps
\begin{align*} \int \frac{\tan ^6(c+d x)}{(a+a \sec (c+d x))^3} \, dx &=\frac{\int (-a+a \sec (c+d x))^3 \, dx}{a^6}\\ &=-\frac{(1-\sec (c+d x)) \tan (c+d x)}{2 a^3 d}-\frac{\int (-a+a \sec (c+d x)) (-2 a+5 a \sec (c+d x)) \, dx}{2 a^5}\\ &=-\frac{x}{a^3}-\frac{(1-\sec (c+d x)) \tan (c+d x)}{2 a^3 d}-\frac{5 \int \sec ^2(c+d x) \, dx}{2 a^3}+\frac{7 \int \sec (c+d x) \, dx}{2 a^3}\\ &=-\frac{x}{a^3}+\frac{7 \tanh ^{-1}(\sin (c+d x))}{2 a^3 d}-\frac{(1-\sec (c+d x)) \tan (c+d x)}{2 a^3 d}+\frac{5 \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{2 a^3 d}\\ &=-\frac{x}{a^3}+\frac{7 \tanh ^{-1}(\sin (c+d x))}{2 a^3 d}-\frac{5 \tan (c+d x)}{2 a^3 d}-\frac{(1-\sec (c+d x)) \tan (c+d x)}{2 a^3 d}\\ \end{align*}
Mathematica [B] time = 0.906319, size = 241, normalized size = 3.65 \[ \frac{2 \cos ^6\left (\frac{1}{2} (c+d x)\right ) \sec ^3(c+d x) \left (-\frac{12 \sin (d x)}{d \left (\cos \left (\frac{c}{2}\right )-\sin \left (\frac{c}{2}\right )\right ) \left (\sin \left (\frac{c}{2}\right )+\cos \left (\frac{c}{2}\right )\right ) \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right ) \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )}+\frac{1}{d \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )^2}-\frac{1}{d \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^2}-\frac{14 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )}{d}+\frac{14 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )}{d}-4 x\right )}{a^3 (\sec (c+d x)+1)^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.08, size = 144, normalized size = 2.2 \begin{align*} -2\,{\frac{\arctan \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) }{d{a}^{3}}}-{\frac{1}{2\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-2}}+{\frac{7}{2\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-1}}+{\frac{7}{2\,d{a}^{3}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) }+{\frac{1}{2\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-2}}+{\frac{7}{2\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-1}}-{\frac{7}{2\,d{a}^{3}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.67691, size = 231, normalized size = 3.5 \begin{align*} -\frac{\frac{2 \,{\left (\frac{5 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac{7 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}}\right )}}{a^{3} - \frac{2 \, a^{3} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac{a^{3} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}}} + \frac{4 \, \arctan \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{3}} - \frac{7 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{a^{3}} + \frac{7 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{a^{3}}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.18403, size = 234, normalized size = 3.55 \begin{align*} -\frac{4 \, d x \cos \left (d x + c\right )^{2} - 7 \, \cos \left (d x + c\right )^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) + 7 \, \cos \left (d x + c\right )^{2} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (6 \, \cos \left (d x + c\right ) - 1\right )} \sin \left (d x + c\right )}{4 \, a^{3} d \cos \left (d x + c\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\tan ^{6}{\left (c + d x \right )}}{\sec ^{3}{\left (c + d x \right )} + 3 \sec ^{2}{\left (c + d x \right )} + 3 \sec{\left (c + d x \right )} + 1}\, dx}{a^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 5.85243, size = 131, normalized size = 1.98 \begin{align*} -\frac{\frac{2 \,{\left (d x + c\right )}}{a^{3}} - \frac{7 \, \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right )}{a^{3}} + \frac{7 \, \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right )}{a^{3}} - \frac{2 \,{\left (7 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 5 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{2} a^{3}}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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